Maria’s Coins

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Maria has $2.45 consisting of coins each worth either $0.05 or $0.25. How many coins worth $0.05 does Maria have?

(1) Maria has fewer than 8 coins worth $0.05 each.

(2) Maria has more than 8 coins worth $0.25 each.

Review: Maria's Coins




Explanation

Given the question, we will put it in algebraic terms, though you might not have to do, if you're great at "spare change" type of math. We'll call the coins nickels and quarters, so we are told that , expressing the equation in cents. We need to find n. Let's go evaluate the data statements, separately first.

Statement (1) indicates that . Does that give us what we need? We can evaluate by cases. The quarters could add up to $2.00; no, actually, that would require 9 nickels, hence too many. The quarters must add up to $2.25, with 4 nickels getting us the rest of the way to $2.45. It's the only possible case, so the statement gives us sufficient information to answer the question definitively. Sufficient.

Statement (2) is of a similar nature. We'll progress by cases. If we have more than 8 quarters, then the smallest number we have is 9, which gives us $2.25. But that is then the only possible number of quarters, because $2.50 would overshoot our total of $2.45. And if we know the quarters add up to $2.25, we can determine the number of nickels exactly. So this statement gives us sufficient information to answer the question.

The correct answer is (D).


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