Explanation
To answer this question, we need to know either both
defect rates,
and
, or an inequality that directly compares the two
rates, in which case we'd know which is greater without knowing their actual
values.Let's see what we get in the
data statements, evaluating separately first.
Statement (1) compares defects, but not runs. That still
permits wildly different cases. For example, the first run might have 10 times
as many defects as the second run, but, for all we know, it could have a
hundred times as many total items, or one-tenth as many items. In those cases
the defect rates would compare different, so the information given in Statement
(1) is insufficient.
Statement (2) has the same logical problem as Statement
(1), as examining cases can show. Insufficient.
Combining the statements, there may be something that we
can do. If there are more defects in the first run, but more items in the
second run, then the first run must have a higher defect rate. We can see this
by considering a limit condition. Say the two runs had the same number of total
items (the r's
are the same). Then, if the first run had higher defects, it has a higher
defect rate:
would be
greater than
. Then, if we make
bigger, that only increase the
difference, because it would increase the denominator of
and make it
smaller. The information we have establishes that the
first run has a higher defect rate.
The correct answer is (C).
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