Albert’s Coins

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Albert has c coins, which is 4 times as many as Bob and as many as Candace. How many more coins do Bob and Candace have together than Albert does, in terms of c?

Review: Albert's Coins


Explanation

In this question, we could pick the numbers for a case, but the algebra looks friendly, so we can write





Where n stands for CaNdice, since Albert already has the variable c, contrary to intuitive naming. We want to obtain n + b, so we can multiply both equations and add them:









Bob and Candace have coins, and Albert has c coins, so the difference is .

Another way to solve this question is to choose values. You can set c = 12, b = 3 and N = 36. The difference is , which is indeed .

The correct answer is (B).


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