Welcome! You are encouraged to register with the site and login (for free). When you register, you support the site and your question history is saved.
Review: Maximum Divisors
Explanation
We are talking about divisors of 1680, which are numbers
that go evenly into 1680. If we make a fraction with 1680 in the numerator and
a divisor in the denominator, the fraction yields an integer. For this to
happen, all of the factors that are present in the divisor must be 1680.
Therefore, 1680 includes n 2's, since
is a divisor, but 1680 does not have m 2's, since 
is not a divisor. Evidently, m is one 2 too many. So let's see how
many 2's are in 1680, through repeated division.
Therefore, the prime factorization is 
.
Therefore, 
and 
.
The correct answer is (C)
If you believe you have found an error in this question or explanation, please contact us and include the question title or URL in your message.